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September 1, 2014

September 1, 2014

Posted by **Jessy** on Sunday, November 24, 2013 at 4:10pm.

a. sin(x)tan(x)=cos(x)/cot^2 (x)

b. (1+tanx)^2=sec^2 (x)+2tan(x)

c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx)

d. tan^2 (x)(1+1/tan^2 x) = 1/(1-sin^2x)

e. sin^3 (x) +cos^3 (x)/(sinx+cosx) = 1-sinxcosx

f. (sinx-cosx+1)/(sinx+cosx-1)= (sinx+1)/cosx

- Trigonometry -
**Steve**, Sunday, November 24, 2013 at 6:55pmif you don't understand it at all, you seriously need to review the most basic trig identities:

sin^2 + cos^2 = 1

tan = sin/cos

cot = 1/tan

With that in mind, and suppressing all the x's for ease of reading,

(a)

sin*tan = sin/cot

= sin*cot/cot^2

= sin(cos/sin) / cot^2

= cos/cot*2

(b)

(1+tan)^2

= 1+2tan+tan^2

= 1+tan^2 + 2tan

= sec^2 + 2tan

(c)

1/sin + 1/cos

= (cos+sin)/(sin*cos)

= (cos+sin)(1/cos)(1/sin)

= (cos+sin)(sec)(csc)

You try the others. These are all pretty basic. The beauty of trig functions is the hundreds of ways they can be arranged and transformed into virtually unrecognizable forms!

- Trigonometry -
**Jessy**, Sunday, November 24, 2013 at 7:04pmThank you for your help. It's just that I didn't take functions in grade 11 and now I'm taking Advanced Functions in grade 12 and I'm difficulty with. Thanks for your help though.

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