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Statistics

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142 out of 507 people were right. Calculate a 95% confidence interval for the proportion of the entire population that could be right. I did some of the work and got .72...don't know what to do with this? Please help.

  • Statistics - ,

    p = 142/ 507 = 0.28

    SD = sqrt(p(1-p)/n)


    0.28-+ 0.039

    (.241, .319)

  • Statistics - ,

    so I could say that with 95% confidence, between 24.1% and 31.9% of the entire population could be right?

  • Statistics - ,

    you know I am getting .0199 SD =srt(.28(1-.28)/506 = .0119? Please check for me again?

  • Statistics - ,

    YES. IF YOUR PROFESSOR SAID THAT YOUR ANSWER SHOULD BE IN PERCENT.

    P = 142/507 = 0.28

    SD = SQRT( .28*.72/507)

    SQRT(0.2016/507) = 0.0199

    Z = 1.96

    0.28-+1.96*0.0199

    0.28-+ 0.039
    ( 0.241, 0.319)

  • Statistics - ,

    I get it now...I was missing a step too! Thanks Much!

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