Posted by **Anon** on Saturday, November 23, 2013 at 10:52pm.

At noon, ship A is 100km west of ship B. Ship A is sailing south at 30km/h and ship B is sailing north at 15km/h. How fast is the distance between the ships changing at 4:00pm?

- Calc -
**Reiny**, Sunday, November 24, 2013 at 12:29am
At a time of t hrs,

let the position of ship A be P and let the position of ship B be Q

Join PQ, and complete the large righ-angled triangle

having a base of 100 and a height of 15t + 30t or 45t

(the horizontal distance between them is always 100 km

PQ^2 = 100^2 + (45t)^2

2 PQ d(PQ)/dt = 0 + 2(45t)(45)

d(PQ)/dt = 2025t/D

at 4:00 , t = 4

PQ = √(100^2 + 180^2) = appr 205.913

d(PQ)/dt = 2025(4)/205.913

= 39.34 km/h

## Answer this Question

## Related Questions

- Calculus 1 - Related Rates I am having trouble finding the equation to use to ...
- Calculus 1 - Related Rates I am having trouble finding the equation to use to ...
- Calculus 1 - Related Rates I am having trouble finding the equation to use to ...
- Calculus 1 - Related Rates I am having trouble finding the equation to use to ...
- Calculus 1 - Related Rates I am having trouble finding the equation to use to ...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- Calculus - "At 9am ship A is 50 km east of ship B. Ship A is sailing north at ...
- Calculus - "At 9am ship A is 50 km east of ship B. Ship A is sailing north at ...
- calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...