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What is y if 6y+1=21y+13
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In the term 21y, what is ther literal coefficient?
a. 2 b. 21 c. 21y d. y I believe it is y
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I mean the answer is B
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4x+5y=27
x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd
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-16y+5y=-11y, not -21y..I think that's your mistake
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solve for 9x-21y=28 -9x+21y=21 in elimination method
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These equations are not solvable. If you add the two equations, you get 0 = 49.
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1- Simplify the radical expression: √250h^4k^5
a) hk√125 b) 5√10h^4k^5 c) 5h^2k^2√10k d) 25hk√10k ** 2- Simplify the
Top answer:
factor out perfect squares. #1. √250h^4k^5 = √25*10*h^4*k^4*k = √(25h^4k^4)*10k = 5h^2k^2
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Question Four
x - 7y = 15 -3x + 21y = - 45
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The 2nd equation is the 1st equation multiplied by -3. So, they are the same line, and there are
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y^4-10y^3+21y^2
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y^2(y^2-10y+21) that help?
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10y^3+y^2-21y
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What is your question?
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10y^3+y^2-21y
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what about it?
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7x+21y-7=x+3y-1 GCF 7
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your statement of 7x+21y-7=x+3y-1 GCF 7 is a false statement. write it as 7x + 21y - 7 = 7(x + 3y -
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is this correct
7x+21y-7=7(x+3y-1)
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expand your answer and see what you get.
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Related Questions
For Question 1-8 Simplify the Radical Expression
*** - My Answer 1.√45 3√5*** 2.√180x^2 6x√5*** 3.√150x^3 k^4
Use the Distributive property to rewrite the expression and simplify.
6(y + 13)+ 21y
Solve for x and y:
35x-21y=10 and 5x-3y=2
factory completely 21y^2+38+5
Factories the following quadratic equations 10Y2 + 21Y-10
what is the factored form of the following expression
x^2-10xy+21y^2
What is the factored form of the following expression?
x^2 - 10xy + 21y^2 (1 point) (x - 3y)(x - 7y) (x + 3y)(x - 7y) (x + 3y)(x
Thanks for the answer Reiny, could you explain the way you solved the factor of 21y^2+38+5
List the terms without changing the expression. 21x+21y
What is the factored form of the following expression?
x^2 - 10xy + 21y^2 (1 point) A. (x - 3y)(x - 7y) B. (x + 3y)(x - 7y) C. (x