The cross-sectional surface area of the screen channel during maximum flow = 0.75 m2. The maximum free surface area in the clean screen = 0.5 m2. Use hL=1C⋅(V2−v2)(2⋅g) for calculating the head loss, the friction coefficient (C) for a clean screen is 0.7.
First, calculate the v in m/s.
2.5
To calculate the velocity (v) in m/s, we need to know the flow rate (Q) in m^3/s and the cross-sectional area (A) in m^2.
Given information:
- The cross-sectional surface area of the screen channel during maximum flow = 0.75 m^2
- The maximum free surface area in the clean screen = 0.5 m^2
Since we don't have the flow rate (Q) provided, we cannot directly calculate the velocity (v). However, if we assume that the flow is fully filled in the screen channel (i.e., the entire cross-sectional area is utilized during maximum flow), then we can calculate the maximum flow rate and subsequently the velocity.
So, assuming full utilization of the cross-sectional surface area during maximum flow, we have:
Q = A * v
0.75 m^2 * v = Q
Now, let's consider the maximum free surface area mentioned in the clean screen: 0.5 m^2. The free surface area is the portion of the cross-sectional area not occupied by the flow. Therefore, during maximum flow, the occupied area is the total area (0.75 m^2) minus the free surface area (0.5 m^2):
Occupied Area = Total Area - Free Surface Area
Occupied Area = 0.75 m^2 - 0.5 m^2
Occupied Area = 0.25 m^2
Since we are assuming full utilization of the cross-sectional area during maximum flow, the occupied area should be equal to the cross-sectional area filled with the flow. Thus:
Occupied Area = A
0.25 m^2 = 0.75 m^2 * v
v = 0.25 m^2 / 0.75 m^2
v = 0.33 m/s
Therefore, the velocity (v) during maximum flow is approximately 0.33 m/s.