Posted by **sydney** on Friday, November 22, 2013 at 6:13pm.

A model rocket is launched with an initial velocity of 160 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by

h = −16t2 + 160t.

How many seconds after launch will the rocket be 350 ft above the ground? Round to the nearest hundredth of a second.

## Answer This Question

## Related Questions

- math - A model rocket is launched with an initial velocity of 250 ft/s. The ...
- math - A model rocket is launched with an initial velocity of 250 ft/s. The ...
- maths - A model rocket is launched with an initial velocity of 250 ft per second...
- algebra - A model rocket is launched upward with an initial velocity of 200 feet...
- college algebra - A model rocket is launches upward with an initial velocity of ...
- pre cal - A toy rocket is launched straight up from the roof of a garage with an...
- Algebra: Quadratic Functions - A model rocket is launched with an initial ...
- math - The height (in feet) of a rocket from ground level is given by the ...
- math - A rocket is launch from the top of an 40 foot cliff with an initial ...
- Math - A rocket is launched from the top of a 50 foot cliff with an initial ...

More Related Questions