Posted by **sydney** on Friday, November 22, 2013 at 6:13pm.

A model rocket is launched with an initial velocity of 160 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by

h = −16t2 + 160t.

How many seconds after launch will the rocket be 350 ft above the ground? Round to the nearest hundredth of a second.

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