March 30, 2017

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A model rocket is launched with an initial velocity of 160 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by
h = −16t2 + 160t.
How many seconds after launch will the rocket be 350 ft above the ground? Round to the nearest hundredth of a second.

  • math - ,

    -16t^2 + 160t = 350
    just use the quadratic formula to solve for t.

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