Posted by **Bailey** on Wednesday, November 20, 2013 at 9:52pm.

1) The first leg of a right triangle is 6 cm longer than its second leg. If the hypotenuse has a length of 8 cm, find the exact lengths of the two legs.

First Leg:

Second Leg:

2) The length of a rectangle is 10 m longer than its width and the area of the rectangle is 480 m2. Find the exact dimensions of the rectangle.

W =

L =

- Algebra, URGENT!!! -
**kuai**, Wednesday, November 20, 2013 at 10:10pm
1. 8^2 x^2(x+6)^2

=

2. 480 = (w+10)w

- Algebra, URGENT!!! -
**Reiny**, Wednesday, November 20, 2013 at 10:37pm
1. x^2 + (x+6)^2 = 8^2

x^2 + x^2 + 12x + 36 - 64 = 0

2x^2 + 12x - 28=0

x^2 + 6x - 14 = 0

x^2 + 6x = 14 , completing the square ....

x^2 + 6x + 9 = 14+9

(x+3)^2 = 23

x+3 = ± √23

x = -3 ± √23

but x has to be positive

so x = √23 - 3

so one leg is √23 - 3 , the other is √23 + 3

#2. solve the equation that kuai gave you

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