Mohammed copies this problem into his notebook
(3.4x10^5)(3.8x10^-9)
A. Use the associateve and commutatitive properties to rearrange the factors.
B. Find the product. Write the product in standard form.
= (3.4)(3.8)(10^5)(10^-9)
= 12.92(10^-4)
= 12.92/10000
= .001292
A. To rearrange the factors using the associative and commutative properties, we can multiply the numerical coefficients and then multiply the powers of 10 separately.
Let's start with the numerical coefficients:
3.4 x 3.8 = 12.92
Now let's multiply the powers of 10:
10^5 x 10^-9
To multiply powers of 10, we add the exponents:
10^5 + (-9) = 10^(-4)
So, the rearranged factors are: 12.92 x 10^(-4).
B. Now, let's find the product. Multiply the numerical coefficient by the power of 10:
12.92 x 10^(-4) = 0.1292
To express the product in standard form, we write it in the form a x 10^b, where a is a number between 1 and 10, and b is an integer.
In this case, we can write the product as 1.292 x 10^(-1).
Therefore, the product of (3.4x10^5)(3.8x10^-9) in standard form is 1.292 x 10^(-1).