math 115
posted by louise on .
Let x be a continuous random variable that follows a normal distribution with a mean of 200 and a standard deviation 25.
Find the value of x so that the area under the normal curve between ì and x is approximately 0.4798 and the value of x is greater than ì.

z = (x  μ) / σ
2.05 (x200)/25
(25)(2.05) = x 200
51.25 = x  200
51.25 + 200 = x 200+ 200
x = 251.25