Friday

March 6, 2015

March 6, 2015

Posted by **Mann** on Tuesday, November 19, 2013 at 12:02am.

- Physics -
**Elena**, Tuesday, November 19, 2013 at 4:03pmm₁a=- m₁g+T₁ …….(1)

- m₂a=T₂- m₂g ……(2)

Iε=(T₂-T₁)R => T₂-T₁ = Iε/R=Ia/R²

If the wheel is disc I=mR²/2 =>

T₂-T₁= Iε/R= mR²a/2R²=ma/2

subtract (2) from (1)

m₁a+ m₂a= - m₁g +T₁- T₂+m₂g.

a(m₁+ m₂) = g(m₂-m₁) - (T₂-T₁)=

= g(m₂-m₁) - ma/2.

a(m₁+ m₂+m/2)= g(m₂-m₁)

a= g(m₂-m₁)/(m₁+ m₂+m/2)

(If the wheel is the hoop I=mR² =>

T₂-T₁= Iε/R= mR²a/R²=ma)

**Answer this Question**

**Related Questions**

Physics 1 - A mass m1 = 4.9 kg rests on a frictionless table and connected by a ...

Physics - Two identical masses are connected by a (massless, stretchless) string...

PHYSICS - A wheel in the shape of a uniform disk of radius R and mass mp is ...

Physics - Blocks of mass m1 and m2 are connected by a massless string that ...

Physics Classical Mechanics` - A wheel in the shape of a uniform disk of radius ...

Physics - A block of mass M resting on a 21.5° slope is shown. The block has ...

Physics - A block of mass M resting on a 21.5° slope is shown. The block has ...

Physics - A block of mass M resting on a 21.5° slope is shown. The block has ...

Physics - We consider the case shown in the figure below. Two objects with ...

Physics - A massless string runs around two massless, frictionless pulleys, ...