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September 1, 2014

September 1, 2014

Posted by **Dee** on Monday, November 18, 2013 at 8:54pm.

- algebra -
**Kuai**, Monday, November 18, 2013 at 9:36pmNo factor

- algebra -
**Steve**, Tuesday, November 19, 2013 at 5:41amyou can tell there are no rational roots because the discriminant is negative. No real roots, no factoring.

You can factor over the irrationals or complex, though, getting

(x-1-√5)(x-1+√5)

and

1/12 (6x+1-i√35)(x+1+i√35)

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