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March 27, 2015

March 27, 2015

Posted by **Graham** on Monday, November 18, 2013 at 8:45pm.

- Calculus -
**Steve**, Tuesday, November 19, 2013 at 12:24amWe need the whole area to be twice the

area under the line y=b.

y(1/2) = 1

y(√b/2) = b

So, integrating along x, we need

∫[0,1/2] 1-4x^2 dx = 2∫[0,√b/2] b-4x^2 dx

Now just evaluate the integrals and solve the polynomial for b.

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