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December 20, 2014

December 20, 2014

Posted by **Dee** on Monday, November 18, 2013 at 8:36pm.

x^3 + 3x^2 − 14x − 20 = 0; {−5}

- college algebra -
**Steve**, Tuesday, November 19, 2013 at 12:27amx^3 + 3x^2 − 14x − 20 = (x+5)(x^2-2x-4)

Now just solve the quadratic for the other two values of x.

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