Posted by Priyank on Monday, November 18, 2013 at 7:59pm.
A hockey puck of mass 0.16 kg, sliding on a nearly frictionless surface of ice with a velocity of 2.0 m/s (E), strikes a second puck at rest with a mass of 0.17 kg. the first puck has a velocity of 1.5 (N 31 E) after the collision. Determine the velocity of the second puck after the collision.
- Physics - LENA, Monday, November 18, 2013 at 9:15pm
please help Ms. SUE!!!!
- electromagnets - anton, Tuesday, November 19, 2013 at 1:56am
a proton flying to the east near the surface of the earth at 1000mls. what is the magnitude of the force the proton feels due to earths magnetic field
- Physics - Elena, Tuesday, November 19, 2013 at 5:01am
Y: 0=m₁u₁sinα - m₂u₂cosβ
m₁v₁-m₁u₁cosα = m₂u₂cosβ …(1)
m₁u₁sinα= m₂u₂cosβ ………...(2)
Divide (2) by (1)
tanβ= m₁u₁sinα/ (m₁v₁-m₁u₁cosα) =
=sinα/ (1- cosα) =3.6
u₂=m₁u₁sinα/ m₂cosβ= 0.16•2•sin31/0.17•sin 74.5 =1 m/s
- Physics - Elena, Tuesday, November 19, 2013 at 5:06am
F=qvB? where q=e
v: m mile/s -> m/s
B= 5•10⁻⁵ T
- Physics - Anonymous, Tuesday, January 21, 2014 at 3:56pm
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