Find the x-intercept and the y-intercept of the linear equation 3x + 4y = 12. Write each intercept as an ordered pair.

To find the x-intercept, let y=0 and solve for x in 3x=12, or x=4. So the ordered pair would be (4,0).

Follow similar rules for the y-intercept.

To find the x-intercept, we need to set y to 0 and solve for x.

Thus, we have:

3x + 4(0) = 12
3x = 12
x = 12/3
x = 4

Therefore, the x-intercept is (4,0).

To find the y-intercept, we need to set x to 0 and solve for y.
Thus, we have:

3(0) + 4y = 12
4y = 12
y = 12/4
y = 3

Therefore, the y-intercept is (0,3).

So, the x-intercept is (4,0) and the y-intercept is (0,3).

To find the x-intercept, we need to set y = 0 in the given equation.

So, 3x + 4(0) = 12.

Simplifying, we get 3x = 12.

Dividing both sides of the equation by 3, we have x = 4.

Therefore, the x-intercept is (4, 0).

To find the y-intercept, we need to set x = 0 in the given equation.

So, 3(0) + 4y = 12.

Simplifying, we get 4y = 12.

Dividing both sides of the equation by 4, we have y = 3.

Therefore, the y-intercept is (0, 3).

So, the x-intercept is (4, 0) and the y-intercept is (0, 3).