(4x-5)^2
Hint: it's not 16x^2-25
Take a look at Kuai's solution to the previous problem, and note the signs.
(4x-5)(4x-5)
16x^2 -20x -20x + 25
= 16x^2 -40x +25
Will it be 16x^2-40x+25
To find the square of the expression (4x-5)^2, you can use the identity (a-b)^2 = a^2 - 2ab + b^2.
In this case, a = 4x and b = 5, so we can substitute these values into the identity:
(4x-5)^2 = (4x)^2 - 2(4x)(5) + (5)^2
Simplifying further:
= 16x^2 - 40x + 25
Therefore, (4x-5)^2 is equal to 16x^2 - 40x + 25.