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March 1, 2015

March 1, 2015

Posted by **McKInsey** on Monday, November 18, 2013 at 12:19pm.

- algebra2 -
**Steve**, Monday, November 18, 2013 at 1:35pmx+y+z = 15000

.01x + .10y + .02z = 210

x = 4z

Now just solve for x,y,z

- algebra2 -
**Henry**, Monday, November 18, 2013 at 6:54pmSee previous post: Mon,11-18-13,11:59 AM.

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