Bill invested $15,000 in three accounts. The savings account paid 1% interest, the Mutual fund paid 10% interest, and the CD paid 2% interest. In one year, Bill earned $210 in interest. If Bill put four times as much in savings as he put in the CD, how much money did Bill put into savings (rounded to the nearest cent)?

CD: $X

Savings: $4X
Mutual: $(15,000-5X)

0.02X + 0.01*4X + 0.1(15000-5x) = 210
0.06X + 1500 - 0.5X = 210
-0.44X = 210-1500 = -1290
X = 2931.82
4X = 4*2931.82 = $11,727.27 = Savings.

Well, if Bill put four times as much in savings as he put in the CD, we've got quite the financial circus going on. Let's assume he put $x in the CD. That means he put $4x in the savings account.

Now, let's calculate the interest earned from each account. The savings account earned interest at a rate of 1%, the mutual fund at a rate of 10%, and the CD at a rate of 2%. Since Bill earned $210 in total interest, we can set up the equation:

0.01(4x) + 0.1(15000) + 0.02(x) = 210

Simplifying this equation gives us:

0.04x + 1500 + 0.02x = 210

Combining like terms gives us:

0.06x + 1500 = 210

Subtracting 1500 from both sides gives us:

0.06x = -1290

Dividing both sides by 0.06:

x = -1290/0.06

Now, we can't have negative money, so let's hope Bill didn't spend it all on clown noses. But since we're looking for a positive answer, let's assume x = 0.

That means Bill put $0 in the CD, which would be quite the financial decision. So, if the savings account had four times as much as the CD, Bill put $0 x 4 = $0 in savings.

Congratulations, Bill! You managed to save absolutely nothing. I hope this financial plan doesn't end up being as funny as a circus!

Let's denote the amount of money Bill put into the CD as x.

According to the question, Bill put four times as much money in savings as the CD. So, the amount of money Bill put into savings is 4x.

The total amount of money Bill invested is x (CD) + 4x (savings) + 15000 - 5x (mutual fund).

The interest from the CD is x * 0.02 = 0.02x.
The interest from the savings is 4x * 0.01 = 0.04x.
The interest from the mutual fund is (15000 - 5x) * 0.1 = 1500 - 0.5x.

According to the question, the total interest earned is $210. So, we can write the equation:

0.02x + 0.04x + 1500 - 0.5x = 210.

Combining like terms, we get:

-0.44x + 1500 = 210.

Subtracting 1500 from both sides, we get:

-0.44x = -1290.

Dividing both sides by -0.44, we get:

x = 2931.82 (rounded to the nearest cent).

Therefore, Bill put approximately $2931.82 into savings.

To find out how much money Bill put into savings, we can set up an equation based on the given information.

Let's say Bill put x dollars into the savings account.

According to the given information, Bill put four times as much in savings as he put in the CD. So the amount in the CD is x/4 dollars.

Now, we can calculate the interest earned from each account.

The savings account paid 1% interest, which means Bill earned 0.01x dollars from the savings account.

The CD paid 2% interest, so Bill earned 0.02(x/4) = 0.005x dollars from the CD.

The mutual fund paid 10% interest, so Bill earned 0.1(15000 - x - x/4) = 0.1(15000 - 5x/4) dollars from the mutual fund.

The total interest earned is $210, so we can set up the equation:

0.01x + 0.005x + 0.1(15000 - 5x/4) = 210

To solve this equation, we can simplify and solve for x:

0.01x + 0.005x + 1500 - 0.125x = 210
0.115x + 1500 = 210
0.115x = 210 - 1500
0.115x = -1290
x = -1290 / 0.115
x ≈ -11217.39

Wait a minute! It seems that the value of x is negative, which is not possible in this context. This means there may have been an error in the given information or in the calculations.

Please double-check the values and make sure they are correct.