How do I find the perimeter of a square with one side listed as 4x + 3 and one more side listed as 3(2x - 5)?
Thank you
If it's a square, the sides are all equal, so
4x+3 = 3(2x-5)
4x+3 = 6x-15
2x = 18
x = 9
so, the preimeter is 36
perimeter 36
To find the perimeter of a square, we need to add up all the sides of the square.
In this case, we have two sides listed: one side is given as 4x + 3, and the other side is given as 3(2x - 5).
To find the perimeter, we need to add these two sides together and then multiply the sum by 4, since a square has four equal sides.
So, let's start by adding the two sides together:
4x + 3 + 3(2x - 5)
First, distribute the 3 to both terms inside the parentheses:
4x + 3 + 6x - 15
Next, combine like terms:
(4x + 6x) + (3 - 15)
10x - 12
Now, multiply the sum by 4 to get the perimeter:
4(10x - 12)
To simplify, distribute the 4 to both terms inside the parentheses:
4 * 10x - 4 * 12
40x - 48
Therefore, the perimeter of the square is 40x - 48.
A square has all sides of equal length. You do not have a square.
For a rectangle, 2[(4x+3)+3(2x - 5)] = ?