Math
posted by Aubrey on .
The Pioneer 10 spacecraft passed the planet Jupiter on December 12, 1973, and exited the solar system on June 14, 1983. The craft traveled from Mars to Jupiter, a distance of approximately 1 billion kilometers, in one year and nine months.
a.Calculate the approximate speed of the craft in kilometers per second.
b.Assuming a constant speed, approximately how many kilometers did Pioneer 10 travel between the time it passed Jupiter and the time it left the solar system?

a)In one year, there is 31 536 000 seconds. The total trip took 641 days, 365(1year)+276(March12December12,9months). 641 days is equal to 55 382 400 seconds. 1billion kilometers/55 382 400seconds=18.056km/s
Therefore the spacecraft was traveling at 18.056km/s.
b)The total amount of days between December 12, 1973 and June 14, 1983 is (including leap days) 3466. 3466 days is equal to 299 462 400 seconds. 18.056km/s*299 462 400s=5 407 093 094km.
Therefore Pioneer 10 traveled 5 407 093 094km from Jupiter to leave the solar system