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November 22, 2014

November 22, 2014

Posted by **Jon** on Friday, November 15, 2013 at 1:09am.

- Trigonometry -
**Jai**, Friday, November 15, 2013 at 2:38amIt would be a lot easier if you draw the figure.

What you would do is just a summation of Forces. Since the system is at equilibrium (forces cancel out), the sum of forces should be zero.

Sum of forces at x-direction:

(T1)*cos(28) - (T2)*cos(35) = 0

Sum of forces at y-direction:

(T1)*sin(28) + (T2)*sin(35) - 100 = 0

Now you have two equation, two unknowns. Solve for T1 and T2. Units in pound-force.

Hope this helps :3

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