Tuesday

October 21, 2014

October 21, 2014

Posted by **enrique** on Thursday, November 14, 2013 at 11:26pm.

down a frictionless ramp (inclined at 30◦

from

the ﬂoor) to the bottom. The block then

slides an additional 23.5 m along the ﬂoor

before coming to stop.

The acceleration of gravity is 9.8 m/s

2.Find the speed of the block at the bottom

of the ramp.

Answer in units of m/s

- physics -
**Henry**, Friday, November 15, 2013 at 10:48pmh = 9.7*sin30 = 4.85 m.

V^2 = Vo^2 + 2g*h

V^2 = 0 + 19.6*4.85 = 95.06

V = 9.75 m/s.

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