Algebra
posted by Anju on .
Of twocar families in a small city, 88% remain twocar families in the following year and 12% become onecar families in the following year. Of onecar families, 72% remain onecar families and 28% become twocar families. Suppose these trends continue for a few years. At present, 4800 families have one car and 4200 families have two cars.
Find the numbers of onecar familes and two car families two years from now.

I assume you are learning about Markov's chains in the study of matrices
end of year 1:
[4200 4800] x
.88 .12
.72 .28
=
[7152 1848]
end of year 2
[7152 1848]
.88 .12
.72 .28
=
[7624.32 1375.68]
I am not absolutely sure if I have the correct order, haven't done this kind of math in almost 20 years.