March 28, 2017

Post a New Question

Posted by on .

A stone is aimed at a cliff of height h with an initial speed of v = 56.0 m/s directed 65.0° above the horizontal, as shown in the Figure below by the arrow. The stone strikes at A, 9.20 s after launching. What is the height of the cliff?

  • Physics - ,

    u=0,theta=65 degrees, t=9.20s
    h= (u^2*sin^2theta)/(2*g)

    solve this and get h..

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question