If you can buy three raffle tickets for $5, how many tickets can you buy for $55? I need to know to different ways to solve this problem...
Method 1:
5/3 = 1.67 each
55/1.67 = 32.9 = 32 tickets for $55.00
Method 2:
Set up a proportion, cross multiply and solve for x.
3/5 = x/55
To solve this problem, there are two different approaches you can use:
1. Division method:
Since you know that three raffle tickets cost $5, you can find the cost of each ticket by dividing the total amount spent by the number of tickets. In this case, $5 divided by 3 gives you the cost of one ticket, which is approximately $1.67.
To find out how many tickets you can buy for $55, divide the total amount spent by the cost of one ticket. $55 divided by $1.67 gives you approximately 32.93. However, since you can't buy a fraction of a ticket, you can buy a maximum of 32 tickets with $55.
2. Proportional method:
You can set up a proportion to solve this problem. Let 'x' be the unknown number of tickets you can buy for $55. The proportion can be set up as:
3 tickets / $5 = x tickets / $55
To solve this proportion, cross-multiply and divide:
3 * $55 = $5 * x
165 = $5x
Dividing both sides by $5:
165 / $5 = x
x = 33
Using this method, you can conclude that with $55, you can buy 33 tickets.