Posted by **Cam** on Wednesday, November 13, 2013 at 4:32pm.

A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of $26 per week with a standard deviation of $8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per week.

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**Kuai**, Wednesday, November 13, 2013 at 4:48pm
26-2.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)),

= ( , ) ?

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**Cam**, Wednesday, November 13, 2013 at 5:40pm
That's what I originally did but it's not one of the correct answers

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**Kuai**, Wednesday, November 13, 2013 at 6:02pm
[ 23.37, 28.63]

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**Cam**, Wednesday, November 13, 2013 at 6:13pm
$9,531 to $11,269

$9,347 to $11,453

$10,028 to $10,772

$9,414 to $11,386

Are my multiple choice

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**Kuai**, Wednesday, November 13, 2013 at 7:13pm
mean 26(400) = $10400

Standard deviation = 8(400) = 3200

10400-+ 2.3263*3200/sqrt(50))

[$9,347, 11,453]

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**Cam**, Wednesday, November 13, 2013 at 9:49pm
Thank you so much !

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