Posted by Cam on Wednesday, November 13, 2013 at 4:32pm.
A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of $26 per week with a standard deviation of $8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per week.

Statistics  Kuai, Wednesday, November 13, 2013 at 4:48pm
262.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)),
= ( , ) ?

Statistics  Cam, Wednesday, November 13, 2013 at 5:40pm
That's what I originally did but it's not one of the correct answers

Statistics  Kuai, Wednesday, November 13, 2013 at 6:02pm
[ 23.37, 28.63]

Statistics  Cam, Wednesday, November 13, 2013 at 6:13pm
$9,531 to $11,269
$9,347 to $11,453
$10,028 to $10,772
$9,414 to $11,386
Are my multiple choice

Statistics  Kuai, Wednesday, November 13, 2013 at 7:13pm
mean 26(400) = $10400
Standard deviation = 8(400) = 3200
10400+ 2.3263*3200/sqrt(50))
[$9,347, 11,453]

Statistics  Cam, Wednesday, November 13, 2013 at 9:49pm
Thank you so much !
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