How do you draw the structure of the reaction of 1-hexene with h2o in the presence of acid

If you mean the acid is a catalyst, then the major product will be 2-hexanol, because Markownikoff's Rule predicts the -OH group will go to the carbon atom with

fewer H atoms (#2 carbon in this case) and the H group goes to the C atom
with more hydrogens (#1 in this case).

To draw the structure of the reaction of 1-hexene with H2O in the presence of acid, you'll first need to understand the reaction mechanism.

1. Start by drawing the structure of 1-hexene, which is a six-carbon chain with a double bond between the first and second carbon atoms.

2. Next, identify the acid that is present. Common acids used in these types of reactions include sulfuric acid (H2SO4) or hydrochloric acid (HCl).

3. The acid protonates the double bond in 1-hexene, meaning it adds a hydrogen ion (H+) to one of the carbon atoms participating in the double bond. This step generates a carbocation intermediate.

4. In the next step, water (H2O) acts as a nucleophile and attacks the positively charged carbocation, removing a hydrogen ion from the adjacent carbon atom. This results in the addition of a hydroxyl group (OH) to the carbon chain.

5. Finally, the acid is regenerated by removing a hydrogen ion from the hydroxyl group that was added in the previous step. This completes the reaction.

Note: The actual position of the hydroxyl group on the carbon chain may vary depending on the specific reaction conditions and the stability of the carbocation intermediate.

By following these steps and understanding the reaction mechanism, you can draw the structure of the reaction between 1-hexene and H2O in the presence of acid.