Posted by Sandra on .
standard deviation 1.2. Random selection of 70 found a mean of 5.2. I have to find a 87% confidence level given this info?

statistics 
PsyDAG,
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability ([1.87]/2) and its Z score.
87% = mean ± Z(SD)
Fill in the values and calculate.