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November 27, 2014

November 27, 2014

Posted by **peter** on Wednesday, November 13, 2013 at 10:05am.

- statistics -
**PsyDAG**, Wednesday, November 13, 2013 at 11:51amFind table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability ([1-.99]/2) and its Z score.

99% = mean ± Z(SEm)

SEm = SD/√n

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