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December 18, 2014

December 18, 2014

Posted by **arpita** on Wednesday, November 13, 2013 at 9:32am.

- algebra -
**Steve**, Wednesday, November 13, 2013 at 12:01pmAssuming a typo, we have

f(a) = 6a^3+5a^2-12a = -4

6a^3+5a^2-12a+4 = 0

(a+2)(2a-1)(3a-2) = 0

. . .

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