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posted by arpita on Wednesday, November 13, 2013 at 9:32am.
given that 6x^3+5a-12a leaves a remainder of -4 when divided by (x-a). what will be the possible value of a ?
Assuming a typo, we have f(a) = 6a^3+5a^2-12a = -4 6a^3+5a^2-12a+4 = 0 (a+2)(2a-1)(3a-2) = 0 . . .
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