three resistances of value 1 ohm, 2 ohm and 3 ohm are connected in parallel.If the
effective resistance of the circuit has to be 1 ohm, the value of the resistance to be connected in series to this circuit should be?
PLZZZZZZZZZZZZZZ ANSWER URGENTTTTT
1/R = 1/1 + 1/2 + 1/3 = 11/6
So, the parallel resistance is 6/11 ohm.
Add 5/11 ohm to make the total 1 ohm.
To find the value of the resistance to be connected in series to the parallel circuit, we can use the formula for the total resistance of resistors connected in parallel:
1/Reff = 1/R1 + 1/R2 + 1/R3
Where Reff is the effective resistance and R1, R2, and R3 are the values of the individual resistances.
In this case, we are given that the effective resistance (Reff) should be 1 ohm. Let's substitute the values of R1, R2, and R3 into the formula:
1/1 = 1/1 + 1/2 + 1/3
Simplifying the equation:
1 = 6/6 + 3/6 + 2/6
1 = 11/6
Since the equation is not balanced, we can't obtain an effective resistance of 1 ohm by connecting the given resistances in parallel.
To achieve an effective resistance of 1 ohm, you would need to adjust the values of the individual resistances or connect different resistances in parallel.
Therefore, there is no specific value of resistance that can be connected in series to achieve an effective resistance of 1 ohm given the resistances 1 ohm, 2 ohm, and 3 ohm connected in parallel.