A 62-kg woman is standing on a scale while riding in an elevator?
As the elevator continues to move up, it has a constant velocity . what is the reading on the scale.?
To determine the reading on the scale, which represents the apparent weight of the woman in the elevator, we need to consider the forces acting on her.
When the elevator is moving with a constant velocity, it means there is no acceleration. According to Newton's first law of motion (also known as the law of inertia), an object at rest or moving at a constant velocity will continue to do so unless acted upon by an external force. Therefore, the net force acting on the woman in the elevator is zero.
The forces acting on the woman in the elevator include her weight (due to gravity) and the normal force exerted by the scale. The normal force is the force exerted by a surface to support the weight of an object resting on it.
Since the elevator is moving with a constant velocity, the woman is not accelerating, and the net force on her is zero. Therefore, the normal force exerted by the scale must be equal in magnitude and opposite in direction to her weight.
The weight of an object is given by the formula: weight = mass × acceleration due to gravity. In this case, the woman's mass is 62 kg. The acceleration due to gravity is approximately 9.8 m/s². Therefore, her weight is 62 kg × 9.8 m/s² = 607.6 N.
Since the normal force exerted by the scale must be equal in magnitude and opposite in direction to her weight, the reading on the scale will also be 607.6 N.