Tuesday

September 30, 2014

September 30, 2014

Posted by **Tram** on Tuesday, November 12, 2013 at 2:02am.

a. how far from the cannon's muzzle (end of cannon where cannon ball exits) would the cannon ball land?

b. at what would the cannon need to be set so as to land half the distance?

My answer: a. 124m . b. 151 degrees

Are my answers correct??

- physic--help --- -
**Steve**, Tuesday, November 12, 2013 at 4:29amhow long does it take to fall 112m?

4.9t^2 = 112

t = 4.78 seconds

horizontal distance traveled is

4.78s * 26.2m/s = 125.26m

Rounding could account for the difference in our answers. I assume your 151° fits the equation, but it seems a bit odd to be firing backwards. Look for an acute angle that will give the same answer.

- physic--help --- -
**Tram**, Tuesday, November 12, 2013 at 9:03amWhere is 4.9 come from?

- physic--help --- -
**Tram**, Tuesday, November 12, 2013 at 9:16amI got it , thank you !

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