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August 23, 2014

August 23, 2014

Posted by **Kim** on Monday, November 11, 2013 at 10:30pm.

- Calculus -
**Reiny**, Monday, November 11, 2013 at 10:39pmlet the ladder be y ft above the ground

x^2 + y^2 = 15^2

when foot is x ft from wall

y^2 = 225-x^2

y = (225-x^2)^(1/2)

2x dx/dt + 2y dy/dt = 0

dy/dt = -2x dx/dt/(2y) = (-x dx/dt)/y

= -2x(1/2)x/√(225 - x^2)

= -x^2/√(225-x^2)

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