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Posted by katrina on Monday, November 11, 2013 at 9:46pm.
What is the force exerted by a catcher's glove on a 0.15-kg baseball moving at 35 m/s that is stopped in 0.02 s?
a = (V-Vo)/t = (0-35)/0.02 = -1750 m/s^2 F = m*a = 0.15 * -1750 = -262.5 N.
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