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Physics

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An object 6.70 cm high is placed 15.1 cm in front of a convex mirror with radius of curvature of 8.55 cm. Where is the image formed?

  • Physics - ,

    1/q + 1/p = 1/f f=r/2 p=15.1
    f= 8.55/2= 4.275

    1/q= 1/f+1/p= 1/4.275 + 1/15.1 = 19.375/64.5525
    take inverse to get q
    q= 3.33

  • Physics - ,

    do=15.1 cm, R=8.55 cm, H= 6.7 cm
    di= ? h=?

    1/do – 1/di = -2/R
    1/di = 1/do+2/R = 1/15.1 +2/8.55.
    di= 3.33 cm
    The virtual image is smaller and closer to the mirror than the object
    h/di =H/do =>
    h=H•di/do = 6.7•3.33/15.1 =1.48 cm

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