Posted by **Joy** on Monday, November 11, 2013 at 12:44pm.

d1 = 2.53 cm +/- .05 cm

d2 = 1.753 m +/- .001 m

0 = 23.5 degrees +/- .5 degrees

v1 = 1.55 m/s +/- .15 m/s

Using the measured quantities above, calculate the following. Express the uncertainty calculated value.

a = 4 v1^2 / d2

## Answer This Question

## Related Questions

- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics (Please Help) - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5...
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics (Please Help) - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5...
- chemistry ap ...urgent! please help me! - The measurement of pH using a glass ...
- Physics - How would one determine the percent uncertainty in theta and in sin of...
- Physics - An object is released from rest and falls in free fall motion. The ...
- Physical Geography - 70 degrees N 0 degrees S 15 degrees E 44 degrees N 160 ...

More Related Questions