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Posted by on Monday, November 11, 2013 at 11:57am.

solve:

2 ln e= ln sqrt of 7/x-2 ln e

what would be x?

  • math - , Monday, November 11, 2013 at 12:05pm

    Assuming parentheses as shown below, and recalling that ln(e) = 1,
    2 ln e= ln sqrt(7/(x-2)) ln e
    2 = ln √(7/(x-2))
    √7/(x-2)) = e^2
    7/(x-2) = e^4
    x-2 = 7e^-4
    x = 2 + 7e^-4

  • math - , Monday, November 11, 2013 at 11:38pm

    Thanks Steve I have it now, But the answer checked out to be e^-4+ln sqrt 7

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