Posted by **Joy** on Monday, November 11, 2013 at 10:51am.

d1 = 2.53 cm +/- .05 cm

d2 = 1.753 m +/- .001 m

0 = 23.5 degrees +/- .5 degrees

v1 = 1.55 m/s +/- .15 m/s

Using the measured quantities above, calculate the following. Express the uncertainty calculated value.

1. d3 = 4 (d1 + d2)

- Physics -
**Count Iblis**, Monday, November 11, 2013 at 11:12am
If f(x1,x2) is a function of x1 and x2 which have independent uncertainties sigma1 and sigma2, then the uncertainty in f(x1,x2) is:

sigmaf = sqrt[sigmaf1^2 +sigmaf2^2]

where sigmaf1 and sigmaf2 are the contributions to the uncertainty in f coming from x1 and x2:

sigmaf1 = f(x1+sigma1,x2) - f(x1,x2)

sigmaf2 = f(x1,x2+sigma2) - f(x1,x2)

Clearly, the uncertainty in d1 makes a contribution to the uncertainty in d3 of:

4*0.05 cm = 0.2 cm

while the uncertainty in d2 makes a contribution to the uncertainty in d3 of:

4*0.1 cm = 0.4 cm

The uncertainty in d3 is then:

sqrt[(0.2 cm)^2 + (0.4 cm)^2] =

0.45 cm

## Answer This Question

## Related Questions

- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics (Please Help) - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5...
- Physics - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5 degrees +/- ....
- Physics (Please Help) - d1 = 2.53 cm +/- .05 cm d2 = 1.753 m +/- .001 m 0 = 23.5...
- chemistry ap ...urgent! please help me! - The measurement of pH using a glass ...
- Physics - How would one determine the percent uncertainty in theta and in sin of...
- Physics - An object is released from rest and falls in free fall motion. The ...
- Physical Geography - 70 degrees N 0 degrees S 15 degrees E 44 degrees N 160 ...

More Related Questions