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April 25, 2014

April 25, 2014

Posted by **McKenna Louise** on Monday, November 11, 2013 at 12:46am.

- Math-Algebra -
**Jai**, Monday, November 11, 2013 at 1:58amThe pressure of a gas varies directly as its temperature:

P = kT

Note that the temperature must be absolute (in Kelvin units). To convert, just add 273 to the degree Celsius.

Substituting the given,

200 lb/in^2 = k (65.5 + 273)

k = 200 / 338.5

k = 0.5908

Now that we know the k, we can use this to solve for the pressure in the second condition. Note that the temperature is in degree F. To convert, T,K = (5/9)*(T,F + 459.7).

P = 0.5908 * (5/9) * (250 + 459.7)

P = 232.94 lb/in^2

Hope this helps :3

- Math-Algebra -
**McKenna Louise**, Monday, November 11, 2013 at 2:35amThank you so very much :)

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