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P(x) = 12x / (1-x)
What are the critical points and where is P(x) increasing and decreasing?

  • Calculus -

    critical points are where P'=0 or is undefined.

    P' = 12/(x-1)^2
    Since P' is always positive, P is always increasing

    P'=0 never, so there are no min/max
    P' is undefined at x=1, the vertical asymptote.

    Enter this function at to see its graph and visualize what the above data indicate.

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