Posted by **Jess** on Sunday, November 10, 2013 at 8:17pm.

P(x) = 12x / (1-x)

What are the critical points and where is P(x) increasing and decreasing?

- Calculus -
**Steve**, Sunday, November 10, 2013 at 8:21pm
critical points are where P'=0 or is undefined.

P' = 12/(x-1)^2

Since P' is always positive, P is always increasing

P'=0 never, so there are no min/max

P' is undefined at x=1, the vertical asymptote.

Enter this function at wolframalpha.com to see its graph and visualize what the above data indicate.

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