2 ln e = ln sq rt. 7/x-2 ln e

without some grouping symbols, I know what you wrote.

my guess is you meant this

2*ln(e)= ln ((7/x)^.5 ) - 2ln(e)

2*1=1/2 ln (7/x) -2
4=1/2 ln(7/x)
ln(7/x)=8
take the antilog
7/x=e^8
then solve for x