Posted by **Anonymous** on Saturday, November 9, 2013 at 2:15pm.

A playground merry-go-round has a radius of R= 2 m and has a moment of inertia Icm= 9×103kg⋅m2 about a vertical axis passing through the center of mass. There is negligible friction about this axis. Two children each of mass m= 20kg are standing on opposite sides at a distance ro= 1.2m from the central axis. The merry-go-round is initially at rest. A person on the ground applies a constant tangential force of F= 2.0×102N at the rim of the merry-go-round for a time Δt= 18s . For your calculations, assume the children to be point masses.

(a) What is the angular acceleration α of the merry-go-round? (in rad/s2)

α=

(b) What is the angular velocity ωfinal of the merry-go-round when the person stopped applying the force? (in rad/s)

ωfinal=

(c) What average power Pavg does the person put out while pushing the merry-go-round? (in Watts)

Pavg=

(d) What is the rotational kinetic energy R.K.Efinal of the merry-go-round when the person stopped applying the force? (in kg⋅m2/s2)

R.K.Efinal=

- PHYSICS (HELP) -
**Elena**, Saturday, November 9, 2013 at 5:15pm
R=2 m, Ic=9000 kgm², r₀=1.2 m, m=20 kg, F=200 N, Δt=18 s.

I=Ic+2I₀=Ic+2m r₀² =

=9000+2201.2²=9057.6 kgm².

M=Iα

α=M/I=FR/I =2002/9057.6 = 0.044 rad/s²

ω=αΔt =0.04418=0.792=0.8 rad/s

P=Fv=P ωR = 2000.82 = 320 W.

KE=Iω²/2 = 9057.60.8²/2 = 2898.4 J.

- PHYSICS (HELP) -
**Anonymous**, Tuesday, November 12, 2013 at 1:15pm
The power is wrong

- PHYSICS (HELP) -
**Greco**, Tuesday, November 12, 2013 at 1:49pm
power is

KE=Ių˛/2 = 90000.8˛/2 = 2880 J.

(Whitout the children)

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