Saturday

April 18, 2015

April 18, 2015

Posted by **Anonymous 11/9/13** on Saturday, November 9, 2013 at 2:14pm.

a. Mean

b. Range

c. Variance

d. Standard deviation

e. What value is affecting the mean and SD of this distribution?

f. Does the mean adequately represent this distribution? If not, what would be a better measure of central tendency for this data set?

Patient Length of Stay LOS-Mean (5) (LOS-Mean)2

(x-x̅) (x-x̅)2

1 1

2 3

3 5

4 3

5 2

6 29

7 3

8 4

9 2

10 1

11 2

I honestly don't understand how to do this. If someone can help me out and guide me in the right direction I would appreciate it. I need to get this right on a test.

- Statistics -
**Anonymous 11/9/13**, Saturday, November 9, 2013 at 2:19pmIt didn't come out right, the numbers 1,3,5,3,2, 29,3, 4, 2, 1, 2 are supposed to be under the column of length of stay. Columns Los-mean (5) and LOS-Mean)2 are intentionally left empty. And the x-x) and (x-x)2 signs are under the LOS mean columns.

I need help, someone please help me with this.

- Statistics -
**kuai**, Saturday, November 9, 2013 at 2:47pma.

mean = (1+3+5+3+2+29+3+4+2+1+2)/11 =55/11= 5

(1-5) =

x (x-x̅) (x-x̅)^2

1 -4 16

3 -2 4

5 0 0

3 -2 4

2 -3 9

29 24 576

3 -2 4

4 -1 1

2 -3 9

1 -4 16

2 -3 9

b.

Range= highest value - lowest value

Range =29-1 = 28

c. variance = (x-x̅)^2 = 648

648/(11-) = 64.8

d. standard deviation = Sqrt(variance) = sqrt(64.8) =8.04984

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