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For the following chemical reaction write the net ionic equation, including the phases.

2HBr (aq) +Ba(OH)2(aq) --> 2H2O(l) +BaBr2 (aq)

  • chemistry - ,

    First separate into ions where appropriate following these rules.
    1. If aq write ions if strong electrolyte; as molecule if not.
    2. Write as molecule if gas
    3. Write as molecule if pure liquid
    4. Write as molecule if solid.

    2H^+(aq) + 2Br^-(aq) + Ba^2+(aq) + 2OH^-(aq) ==> 2H2O(l) + Ba^2+(aq) + 2Br^-(aq)

    Now to turn the complete ionic equation into the net ionic equation just cancel the ions common to each side. The net ionic equation is what is left.
    I see Br^- on both sides. I see Ba^2+ on both sides. Cancel those on both sides. That leaves you with
    2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)

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