Posted by **Michael** on Saturday, November 9, 2013 at 9:08am.

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3 days with a standard deviation of 1.2 days.

Test the claim that the mean hospital stay after childbirth for this hospital is significantly longer than the national mean of 2.1 days.

What is the p-value?

A) 0.9312

B) 0.0688

C) 0.1376

D) 0.164

- Statistics -
**PsyDAG**, Saturday, November 9, 2013 at 10:59am
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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