Saturday

August 30, 2014

August 30, 2014

Posted by **arzam** on Saturday, November 9, 2013 at 3:06am.

(ii)Find the sum of the first 200 even numbers.

(iii)Find the sum of the first 200 odd numbers.

(B)(i)Use the formula at the beginning of the question to find the sum of the first 2n natural numbers.

(ii)Find a formula, in its simplest form, for 1+3+5+7+9+...+(2n-1)

- Math -
**Steve**, Saturday, November 9, 2013 at 5:15amusing induction

if n=1, 2 = 1(2) = 2

assuming true for n=k,

check for n=k+1:

2+...+2k+2k+2

= k(k+1) + 2k+2

= k(k+1) + 2(k+1)

= (k+1)(k+2)

as desired.

1+3+5+...+(2n-1) = n^2

**Related Questions**

Maths - When the first n positive integers are added together, their sum is ...

math - Hi. I'm having trouble with the summation of n from i=2 of ((2^n-i)(2^n...

algebra - So... I know the answer to the question because it's something we ...

math - (b) the digits of a positive integer having three digits are in A.P and ...

math - (b) the digits of a positive integer having three digits are in A.P and ...

college math - I do not understand a problem from a text book or how to solve ...

Algebra - I have a few problems I need some help with. The first is Evaluate ...

algebra - Find two consecutive positive integers such that the sum of their ...

Calculus II - Find the sum of the series (infinity above sigma) signma and n = ...

Algebra - The sum of two consecutive odd integers is 24. Which equation can be ...