Wednesday

April 16, 2014

April 16, 2014

Posted by **JOHN** on Friday, November 8, 2013 at 11:56pm.

2) A communications tower is located at the top of a steep hill, as shown. The angle of inclination of the hill is 58°. A guy wire is to be attached to the top of the tower and to the ground, 150 m downhill from the base of the tower. The angle α in the figure is determined to be 7°. Find the length of cable required for the guy wire. (Round your answer to the nearest meter.)

Thank you!

- PRE-CALC HELP -
**Steve**, Saturday, November 9, 2013 at 12:19am#1

convert to rectangular coordinates and subtract to get a distance of 24.9

#2

assuming the angle α is the angle between the ground and the cable, then using the law of sines, the distance d of the cable is

d/sin148° = 150/sin35°

- PRE-CALC HELP -
**kuai**, Saturday, November 9, 2013 at 12:41am1. x^2 = 22^2+ 27^2 -2(22)(27)cos60

x^2 =1213 -1188cos60

x^2 =619

x= 24.9 miles

- go with kuai -
**Steve**, Saturday, November 9, 2013 at 5:26amkuai's solution is better, because the assignment is evidently involving the law of sines/cosines.

also, less work!

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