Posted by **JAYZ** on Friday, November 8, 2013 at 8:27pm.

A potter’s wheel of radius 53.13 cm and mass 106.4 kg is freely rotating at 47.1 rev/min. The potter can stop the wheel in 5.65 s by pressing a wet rag against the rim and exerting a radially inward force of 66.2 N.

What is the angular acceleration of the wheel?

- Physics -
**Damon**, Friday, November 8, 2013 at 8:36pm
The only information of any use in this lengthy paragraph is:

wheel stops from 47.1 rev/min in 5.65 sec

we want radians and seconds

47.1 rev/min * 2 pi rad/rev * 1 min/60 s

= 4.93 radians/second

acceleration = change in velocity/change in time

= 4.93 rad/s / 5.65 s

= .873 radians/second^2

- Physics -
**Damon**, Friday, November 8, 2013 at 8:38pm
Oh, and the answer is negative (deacceleration)

- Physics -
**JAYZ**, Friday, November 8, 2013 at 9:33pm
yea i had the answer but forgot the negative, thanks man! really appreciate it!

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