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August 23, 2014

August 23, 2014

Posted by **Anonymous** on Friday, November 8, 2013 at 8:20pm.

sec x/(sec x -tan x)=sec^2 x +sec x tan x

- Precalculus -
**Damon**, Friday, November 8, 2013 at 8:28pmleft side

(1/cos) /(1/cos -sin/cos)

1/(1 - sin)

right side

1/cos^2 + sin/cos^2

(1+sin)/(1-sin^2)

(1+sin) / [(1+sin)(1-sin) ]

1/(1-sin) remarkable :)

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